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simplify flag parsing code in permit

This commit is contained in:
Connor Olding 2024-07-16 11:22:04 -07:00
parent 8904f22242
commit 9d5a240d55

View file

@ -25,7 +25,7 @@ permit() { ### @- conditionally set executable permissions on each of its argume
### already executable by the current user are skipped. arguments that do
### not appear to refer to an existing file are passed through to chmod.
### directories are never recursed.
unset __permit_4 __permit_a __permit_f __permit_h __permit_m __permit_n __permit_x || return
unset __permit_4 __permit_a __permit_f __permit_h __permit_m __permit_x || return
__permit_h="[-a | -A] [-e | -f | -d] [--] {files...}"
if [ $# = 0 ]; then
@ -33,43 +33,34 @@ permit() { ### @- conditionally set executable permissions on each of its argume
return 64;
fi
__permit_m=e # everything
__permit_m=e # mode
__permit_a=0 # automatic
__permit_n=$#
while [ $((__permit_n-=1)) -ge 0 ]; do
__permit_f="$1"
case "$__permit_f" in
unset __permit_stop || return
for __permit_f; do
shift
case "${__permit_stop+:}$__permit_f" in
(/\?|-h|-help|--help)
printf 'usage: permit %s\n' "$__permit_h"
return 0;;
(--)
shift
while [ $((__permit_n-=1)) -ge 0 ]; do
set -- "$@" "$1"
shift
done
break;;
__permit_stop=1;;
(-?*)
shift
while __permit_f="${__permit_f#?}"; [ -n "$__permit_f" ]; do
case "${__permit_f}" in
(a*) __permit_a=1;; # automatic (on)
(A*) __permit_a=0;; # automatic (off)
(e*) __permit_m=e;; # everything
(f*) __permit_m=f;; # files only
(d*) __permit_m=d;; # directories only
(*)
printf >&2 'permit: unknown flag: -%.1s\n' "$__permit_f"
return 64;;
esac
done;;
(*)
shift
set -- "$@" "$__permit_f";;
esac
done