From dfe69c396f339a2164031e18604707d4f773ef67 Mon Sep 17 00:00:00 2001
From: Connor <cloningdonor@gmail.com>
Date: Tue, 11 Sep 2018 14:03:16 -0700
Subject: [PATCH]

---
 ac_encode.py | 11 ++---------
 1 file changed, 2 insertions(+), 9 deletions(-)

diff --git a/ac_encode.py b/ac_encode.py
index 1700b04..9ed7171 100644
--- a/ac_encode.py
+++ b/ac_encode.py
@@ -27,8 +27,6 @@ def encode(string, c0=BETA0, c1=BETA1, adaptive=True):
 
     b = ONE
     a = 0
-    tot0 = 0
-    tot1 = 0
     if not adaptive:
         p0 = c0 / (c0 + c1)
     ans = ""
@@ -54,15 +52,13 @@ def encode(string, c0=BETA0, c1=BETA1, adaptive=True):
 
         if c == '1':
             a = boundary
-            tot1 += 1
             if adaptive:
                 c1 += 1
         elif c == '0':
             b = boundary
-            tot0 += 1
             if adaptive:
                 c0 += 1
-            # ignore other characters
+        # ignore other characters
 
         while a >= HALF or b <= HALF:  # output bits
             if a >= HALF:
@@ -116,8 +112,6 @@ def decode(string, N, c0=BETA0, c1=BETA1, adaptive=True):
 
     b = ONE
     a = 0
-    tot0 = 0
-    tot1 = 0
     model_needs_updating = True
     if not adaptive:
         p0 = c0 / (c0 + c1)
@@ -129,6 +123,7 @@ def decode(string, N, c0=BETA0, c1=BETA1, adaptive=True):
         if N <= 0:
             break  # out of the string-reading loop
         assert N > 0
+
         # (u,v) is the current "encoded alphabet" binary interval,
         # and halfway is its midpoint.
         # (a,b) is the current "source alphabet" interval,
@@ -161,7 +156,6 @@ def decode(string, N, c0=BETA0, c1=BETA1, adaptive=True):
 
             if boundary <= u:
                 ans += "1"
-                tot1 += 1
                 if adaptive:
                     c1 += 1
                 a = boundary
@@ -169,7 +163,6 @@ def decode(string, N, c0=BETA0, c1=BETA1, adaptive=True):
                 N -= 1
             elif boundary >= v:
                 ans += "0"
-                tot0 += 1
                 if adaptive:
                     c0 += 1
                 b = boundary